use a for..break because we can't depend on count

as commented in http://aspell.net/sf-issue-files/11b76e92/632d/test.c
` aspell_dict_info_list_size(dlist)` will allways return `0` for some
reason. execute `aspell_dict_info_enumeration_next(dels)` until it
returns nil.

aspell.go

@@ -180,26 +180,24 @@ type Dict struct {
 
 // Dicts returns the list of available aspell dictionaries.
 func Dicts() []Dict {
+	var result []Dict
 	config := C.new_aspell_config()
 	dlist := C.get_aspell_dict_info_list(config)
 	C.delete_aspell_config(config)
 
-	count := int(C.aspell_dict_info_list_size(dlist))
-	result := make([]Dict, count)
-
 	dels := C.aspell_dict_info_list_elements(dlist)
-	for i := 0; i < count; i++ {
+	for {
 		entry := C.aspell_dict_info_enumeration_next(dels)
 		if entry == nil {
 			break
 		}
-		result[i] = Dict{
+		result = append(result, Dict{
 			name:   C.GoString(entry.name),
 			code:   C.GoString(entry.code),
 			jargon: C.GoString(entry.jargon),
 			size:   C.GoString(entry.size_str),
 			module: C.GoString(entry.module.name),
-		}
+		})
 	}
 	C.delete_aspell_dict_info_enumeration(dels)