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* n+1 카드게임 * 교점에 별 만들기 * 귤 고르기 * 섬 연결하기 * n진법 뒤집기
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from collections import deque | ||
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INF = int(1e9) | ||
# 일단 카드를 모두 갖고, 카드를 사용해야할 때 coin 지불 | ||
def solution(coin, cards): | ||
global my_cards, cost, n | ||
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n = len(cards) | ||
cards = deque(cards) | ||
my_cards = [] | ||
cost = [INF] * (n+1) | ||
for _ in range(n//3): | ||
card = cards.popleft() | ||
my_cards.append(card) | ||
cost[card] = 0 | ||
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answer = 1 | ||
while len(cards) > 0: | ||
# 카드 두 장 뽑기 | ||
for _ in range(2): | ||
card = cards.popleft() | ||
my_cards.append(card) | ||
cost[card] = 1 | ||
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_cost, _cards = find() | ||
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if _cost > coin: | ||
break | ||
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coin -= _cost | ||
for card in _cards: | ||
my_cards.remove(card) | ||
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answer += 1 | ||
return answer | ||
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# 가장 저렴한 비용으로 n+1이 되는 카드 찾기 | ||
def find(): | ||
_cost = INF | ||
_cards = [] | ||
for card in my_cards: | ||
temp = cost[card] + cost[n+1-card] | ||
if _cost > temp: | ||
_cost = temp | ||
_cards = [card, n+1-card] | ||
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return (_cost, _cards) |
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def solution(n): | ||
third = [] | ||
while n > 0: | ||
third.append(n%3) | ||
n //= 3 | ||
answer = 0 | ||
m = 0 | ||
for k in third[::-1]: | ||
answer += k *(3**m) | ||
m += 1 | ||
return answer |
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INF = int(1e15) | ||
def solution(line): | ||
points = set() | ||
min_x = INF | ||
min_y = INF | ||
max_x = -INF | ||
max_y = -INF | ||
N = len(line) | ||
for i in range(N-1): | ||
A, B, E = line[i] | ||
for j in range(i+1, N): | ||
C, D, F = line[j] | ||
xc = B*F - E*D | ||
yc = E*C - A*F | ||
p = A*D - B*C | ||
if p == 0: | ||
continue | ||
x = xc / p | ||
y = yc / p | ||
int_x = int(x) | ||
int_y = int(y) | ||
if x == int_x and y == int_y: | ||
points.add((int_x, int_y)) | ||
min_x, min_y = min(min_x, int_x), min(min_y, int_y) | ||
max_x, max_y = max(max_x, int_x), max(max_y, int_y) | ||
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result = [["."] * (abs(max_x-min_x)+1) for _ in range(abs(max_y-min_y)+1)] | ||
for x, y in points: | ||
result[y-min_y][x-min_x] = "*" | ||
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answer = [] | ||
for row in result: | ||
answer.append("".join(row)) | ||
return answer[::-1] |
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def solution(k, tangerine): | ||
count = [0] * (10_000_000+1) | ||
for t in tangerine: | ||
count[t] += 1 | ||
count.sort(reverse=True) | ||
i = 0 | ||
while k > 0: | ||
k -= count[i] | ||
i += 1 | ||
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return i |
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def find_parent(node): | ||
if parent[node] != node: | ||
parent[node] = find_parent(parent[node]) | ||
return parent[node] | ||
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def union(node1, node2): | ||
parent1 = find_parent(node1) | ||
parent2 = find_parent(node2) | ||
if parent1 < parent2: | ||
parent[parent2] = parent1 | ||
else: | ||
parent[parent1] = parent2 | ||
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def solution(n, costs): | ||
global parent | ||
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parent = [0] * n | ||
for i in range(n): | ||
parent[i] = i | ||
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answer = 0 | ||
costs.sort(key = lambda x: x[2]) | ||
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for node1, node2, cost in costs: | ||
if find_parent(node1) != find_parent(node2): | ||
union(node1, node2) | ||
answer += cost | ||
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return answer |