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3주차 과제(박민규) #18

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@ps9319 ps9319 commented May 12, 2024

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@ps9319 ps9319 self-assigned this May 12, 2024
Comment on lines +22 to +39
allApplicantNum.put("PG", 0);
allApplicantNum.put("PM", 0);
allApplicantNum.put("DE", 0);

// value = Registration
for (String key : allRegistration.keySet()){
Registration registration = allRegistration.get(key);
allApplicantNum.put(registration.getHopeField(), allApplicantNum.get(registration.getHopeField()) + 1);
}

// WEB, APP, AI, GAME
// key = firstPriority, secondPriority
Map<String, int[]> allApplicantPriority = new HashMap<>();

allApplicantPriority.put("WEB", new int[2]);
allApplicantPriority.put("APP", new int[2]);
allApplicantPriority.put("AI", new int[2]);
allApplicantPriority.put("GAME", new int[2]);
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put put put put 해서 메소드 하나에 별도로 인덱스를 접근해서 초기화 하는 코드 하나로 지금 거의 10줄이 넘게 소요되고 있죠? 차라리 init 함수를 따로 빼도 좋겠습니다.

Comment on lines +42 to +51
for (String key : allRegistration.keySet()){
Registration registration = allRegistration.get(key);
int[] firstPriority = allApplicantPriority.get(registration.getFirstPriority());
int[] secondPriority = allApplicantPriority.get(registration.getSecondPriority());

firstPriority[0] += 1;
secondPriority[1] += 1;

}

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1씩 늘려가며 집계하는 코드는 좋지 않습니다. 나중에 100만건이 있으면 100만번 더하는 것이 좋을까요? 다시 고민!

Comment on lines +31 to +43
if(!allMajor.containsKey(major)){
allMajor.put(major, 0);
}
if(!allMajor.containsKey(doubleMajor)){
allMajor.put(doubleMajor, 0);
}
if(!allMajor.containsKey(minor)){
allMajor.put(minor, 0);
}

allMajor.put(major, allMajor.get(major) + 1);
allMajor.put(doubleMajor, allMajor.get(doubleMajor) + 1);
allMajor.put(minor, allMajor.get(minor) + 1);
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르블랑의 법칙

나는 현재 충분히 아름다운 코드를 짜고 있는가?
우리 모두는 자신이 짠 쓰레기 코드를 쳐다보며 나중에 손보겠다고 생각한 경험이 있다. 우리 모두는 대충 짠 프로그램이 돌아간다는 사실에 안도감을 느끼며 그래도 안 돌아가는 프로그램보다 돌아가는 쓰레기가 좋다고 스스로를 위로한 경험이 있다. 다시 돌아와 나중에 정리하겠다고 다짐했었다. 물론 그때 그 시절 우리는 르블랑의 법칙을 몰랐다. 나중은 결코 오지 않는다.

Comment on lines +15 to +24
public DesiredTimeMapper getAllDesiredTime() {
Map<String, DesiredTime> allDesiredTime = db.getAllDesiredTime();
for (String key : allDesiredTime.keySet()){
DesiredTime desiredTime = allDesiredTime.get(key);
for (int[] times: desiredTime.getDesiredTime()){
int startTime = times[0];
int endTime = times[1];


}
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return이 없는데 덜 짜신건가요??

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네...덜 짰습니다

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3 participants