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144.二叉树的前序遍历.java
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144.二叉树的前序遍历.java
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import java.util.ArrayList;
import java.util.List;
import java.util.Stack;
/*
* @lc app=leetcode.cn id=144 lang=java
*
* [144] 二叉树的前序遍历
*
* https://leetcode-cn.com/problems/binary-tree-preorder-traversal/description/
*
* algorithms
* Medium (64.45%)
* Likes: 212
* Dislikes: 0
* Total Accepted: 74.5K
* Total Submissions: 115.5K
* Testcase Example: '[1,null,2,3]'
*
* 给定一个二叉树,返回它的 前序 遍历。
*
* 示例:
*
* 输入: [1,null,2,3]
* 1
* \
* 2
* /
* 3
*
* 输出: [1,2,3]
*
*
* 进阶: 递归算法很简单,你可以通过迭代算法完成吗?
*
*/
// @lc code=start
class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode(int x) { val = x; }
}
/*
//recursion
class Solution {
public List<Integer> preorderTraversal(TreeNode root) {
ArrayList<Integer> list = new ArrayList<>();
helper(list,root);
return list;
}
public void helper(ArrayList<Integer> list, TreeNode node){
if(node == null)
return;
list.add(node.val);
helper(list,node.left);
helper(list,node.right);
}
} */
//iteration
class Solution {
public List<Integer> preorderTraversal(TreeNode root) {
ArrayList<Integer> list = new ArrayList<>();
Stack<TreeNode> stack = new Stack<>();
if(root == null)
return list;
stack.push(root);
while(!stack.isEmpty()){
TreeNode node = stack.pop();
list.add(node.val);
if(node.right != null)
stack.push(node.right);
if(node.left != null)
stack.push(node.left);
}
return list;
}
}
// @lc code=end