反转一个单链表。
示例:
输入: 1->2->3->4->5->NULL 输出: 5->4->3->2->1->NULL
进阶:
你可以迭代或递归地反转链表。你能否用两种方法解决这道题?
题目标签:Linked List
题目链接:LeetCode / LeetCode中国
Language | Runtime | Memory |
---|---|---|
cpp | 8 ms | 1.2 MB |
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* reverseList(ListNode* head) {
if (!head || !head->next) { return head; }
ListNode* p = head;
ListNode* q = head->next;
while (q->next) {
ListNode* r = q->next;
q->next = p;
p = q;
q = r;
}
q->next = p;
head->next = NULL;
return q;
}
};