给定一个二叉树,返回它的 后序 遍历。
示例:
输入: [1,null,2,3] 1 \ 2 / 3 输出: [3,2,1]
进阶: 递归算法很简单,你可以通过迭代算法完成吗?
题目标签:Stack / Tree
题目链接:LeetCode / LeetCode中国
Language | Runtime | Memory |
---|---|---|
cpp | 8 ms | 9.2 MB |
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> postorderTraversal(TreeNode* root) {
vector<int> res;
stack<pair<bool, TreeNode*>> stk;
stk.push({false, root});
while (!stk.empty()) {
auto p = stk.top();
stk.pop();
bool flag = p.first;
TreeNode* node = p.second;
if (!node) continue;
if (flag) {
res.push_back(node->val);
} else {
stk.push({true, node});
stk.push({false, node->right});
stk.push({false, node->left});
}
}
return res;
}
};