Is it possible to overload the call operator?

[Cazadorro]

I see subscript is overloadable, but I don't see anything about the call operator (). There's no negative documentation that this is not available AFAICT, and there's lots of magic methods usable I don't understand beyond __subscript.

[natevm]

For construction at least, you’d use __init(params…). That’s not the same as call operator overloading, but figured I’d put it out there for context.

[csyonghe]

Overloading for operator() is not supported yet. It is possible for us to add the feature, but we are currently very short on engineering resources.

[csyonghe]

This is now supported, closing now.

struct MyFunctor
{
       int operator()(float v) { ... }
}

void test()
{
    let f = MyFunctor();
    f(2.0f);
}

[natevm]

Awesome! Looking forward to using this.

[Cazadorro]

Damn you guys are doing overtime on this project! Seriously did not expect this in for a very long time!