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088_MergeSortedArray88.java
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088_MergeSortedArray88.java
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/**
* Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as
* one sorted array.
*
* Note:
* You may assume that nums1 has enough space (size that is greater or equal to
* m + n) to hold additional elements from nums2. The number of elements
* initialized in nums1 and nums2 are m and n respectively.
*
*/
public class MergeSortedArray88 {
public void merge(int[] nums1, int m, int[] nums2, int n) {
if (n == 0) return;
int i = m-1;
int j = n-1;
while (i >= 0 && j >= 0) {
if (nums1[i] >= nums2[j]) {
nums1[i+j+1] = nums1[i];
i--;
} else {
nums1[i+j+1] = nums2[j];
j--;
}
}
while (j >= 0) {
nums1[j] = nums2[j];
j--;
}
}
/**
* https://leetcode.com/problems/merge-sorted-array/discuss/29505/1-Line-Solution
*/
public void merge2(int[] nums1, int m, int[] nums2, int n) {
while (n > 0) nums1[m+n-1] = (m == 0 || nums2[n-1] > nums1[m-1]) ? nums2[--n] : nums1[--m];
}
}