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day04.html
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<!DOCTYPE html>
<html lang="en-us">
<head>
<title>2020\day04.nim</title>
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<body>
<header><nav><em class="star"><a href="https://pietroppeter.github.io/adventofnim/index.html">🎄👑 adventofnim</a></em></header>
<hr><main>
<h1>--- Day 4: Passport Processing ---</h1>
<p>I came with such an ugly solution that now I really <em>have to learn regexs</em> for good</p>
<pre><code class="nim">type
PassField = enum
byr, iyr, eyr, hgt, hcl, ecl, pid, cid
PassPort = Table[PassField, string]
Input = distinct string
let
input = "2020/input04.txt".readFile.Input
example = """ecl:gry pid:860033327 eyr:2020 hcl:#fffffd
byr:1937 iyr:2017 cid:147 hgt:183cm
iyr:2013 ecl:amb cid:350 eyr:2023 pid:028048884
hcl:#cfa07d byr:1929
hcl:#ae17e1 iyr:2013
eyr:2024
ecl:brn pid:760753108 byr:1931
hgt:179cm
hcl:#cfa07d eyr:2025 pid:166559648
iyr:2011 ecl:brn hgt:59in""".Input
proc parse(line: string): seq[tuple[f: PassField, s: string]] =
for s in line.split:
if s == "":
continue
let t = s.split(':')
result.add (parseEnum[PassField](t[0]), t[1])
proc parse(batch: Input): seq[PassPort] =
var p: PassPort
p = initTable[PassField, string]()
for line in batch.string.splitLines:
if line.len == 0:
result.add p
p = initTable[PassField, string]()
for v in line.strip.parse:
p[v.f] = v.s
result.add p
proc isValid(p: PassPort): bool =
p.len == 8 or (p.len == 7 and cid notIn p)
proc countValid(s: seq[PassPort]): int =
for p in s:
if p.isValid:
inc result
let
pass0 = example.parse
pass1 = input.parse
echo pass0.countValid
echo pass1.countValid</code></pre>
<pre><samp>2
216</samp></pre>
<p>That's the right answer! You are <em class="star">one gold star</em> closer to saving your vacation.</p>
<pre><code class="nim">const
colors = "amb blu brn gry grn hzl oth".split()
proc validHgt(s: string): bool =
var num: BiggestInt
if s.endsWith("cm"):
parseBiggestInt(s[0 .. ^3], num) != 0 and num >= 150 and num <= 193
elif s.endsWith("in"):
parseBiggestInt(s[0 .. ^3], num) != 0 and num >= 59 and num <= 76
else:
false
template myEcho(s: string) =
discard
proc isGood(p: PassPort): bool =
if not p.isValid:
return false
var num: BiggestInt
myEcho $p
if parseBiggestInt(p[byr], num) != 4 or num < 1920 or num > 2002:
myEcho "invalid p[byr] " & p[byr]
return false
myEcho "valid p[byr] " & p[byr]
if parseBiggestInt(p[iyr], num) != 4 or num < 2010 or num > 2020:
myEcho "invalid p[iyr] " & p[iyr]
return false
myEcho "valid p[iyr] " & p[iyr]
if parseBiggestInt(p[eyr], num) != 4 or num < 2020 or num > 2030:
myEcho "invalid p[eyr] " & p[eyr]
return false
myEcho "valid p[eyr] " & p[eyr]
if p[ecl] notIn colors:
myEcho "invalid p[ecl] " & p[ecl]
return false
myEcho "valid p[ecl] " & p[ecl]
var color: string
if not p[hcl].startsWith("#") or p[hcl].len != 7 or
p[hcl].parseWhile(color, {'0' .. '9', 'a' .. 'f'}, start = 1) != 6:
myEcho "invalid p[hcl] " & p[hcl]
return false
myEcho "valid p[hcl] " & p[hcl]
if not (p[hgt].validHgt):
myEcho "invalid p[hgt] " & p[hgt]
return false
myEcho "valid p[hgt] " & p[hgt]
var digits: string
if p[pid].parseWhile(digits, {'0' .. '9'}) != 9:
myEcho "invalid p[pid] " & p[pid]
return false
myEcho "valid p[pid] " & p[pid]
myEcho "ALLGOOD"
return true
proc countGood(s: seq[PassPort]): int =
for p in s:
if p.isGood:
inc result
echo pass0.countGood
echo pass1.countGood</code></pre>
<pre><samp>2
150</samp></pre>
<p>That's the right answer! You are <em class="star">one gold star</em> closer to saving your vacation.</p>
</main>
<hr>
<small>
<p>github repo for all my solutions: 🎄👑<a href="https://github.com/pietroppeter/adventofnim">adventofnim</a>;</p>
<p>html output powered by 🐳<a href="https://github.com/pietroppeter/nimib">nimib</a>.</p>
</small>
</body>
</html>