-
Notifications
You must be signed in to change notification settings - Fork 154
/
1728 - Inversion Probability.cpp
54 lines (50 loc) · 1.41 KB
/
1728 - Inversion Probability.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
/*
Problem Name: Inversion Probability
Problem Link: https://cses.fi/problemset/task/1728
Author: Sachin Srivastava (mrsac7)
*/
#include<bits/stdc++.h>
using namespace std;
template<typename... T>
#define error(args...) { string _s = #args; replace(_s.begin(), _s.end(), ',', ' '); stringstream _ss(_s); istream_iterator<string> _it(_ss); err(_it, args); }
void err(istream_iterator<string> it) {}
template<typename T, typename... Args>
void err(istream_iterator<string> it, T a, Args... args) {cerr << *it << "=" << a << ", "; err(++it, args...);}
#define int long long
#define pb push_back
#define F first
#define S second
const int inf = 1LL<<62;
const int md = 1000000007;
void solve(){
int n, r[105];
long double p[105][105] = {0};
cin>>n;
for (int i = 0; i < n; i++) {
cin>>r[i];
}
long double ans = 0;
for (int i = 0; i < n; i++) {
for ( int j = i + 1; j < n; j++) {
for (int k = 1; k <= r[i]; k++) {
p[i][j] += 1.0/r[i]*(((k - 1) >= r[j])?1.0:(k-1.0)/r[j]);
}
ans += p[i][j];
}
}
cout<<setprecision(6)<<fixed;
cout<<ans;
}
signed main(){
ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#ifdef LOCAL
freopen("input.txt", "r" , stdin);
freopen("output.txt", "w", stdout);
#endif
int t=1;
//cin>>t;
for (int i = 1; i <= t; i++) {
solve();
cout<<'\n';
}
}