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"a" difference between HDDM and HSSM #282

Answered by AlexanderFengler
JoeSu112 asked this question in Q&A

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Hi @JoeSu112 ,

a_hssm should be a_hddm / 2 (that is what you observe right?).

The difference is that HSSM will treat boundaries consistently (intended) as [-a, a] whereas in HDDM boundaries were treated as [0, a] for basic HDDM functionality and as [-a, a] in the HDDMnn classes.

Sorry about the confusion we should make a note on this in the documentation.
Let me know if any question remains.

Best,
Alex

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@JoeSu112

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