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190.c
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190.c
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#include <stdio.h>
#include <stdint.h>
/*
https://graphics.stanford.edu/~seander/bithacks.html
*/
void print_bits(uint32_t n) {
int i = 32;
while(i--){
if ((n >> i) & 1)
printf("1");
else
printf("0");
}
printf("\n");
}
/* 32 steps */
uint32_t reverseBits_1(uint32_t n) {
uint32_t ret = 0;
int i = 31;
while (i--) { // 31 times
ret += n & 0x01;
n >>= 1;
ret <<= 1;
}
ret += n & 0x01;
return ret;
}
/* 5 steps : 5 * lg(N) operations */
uint32_t reverseBits_2(uint32_t n) {
uint32_t t = n;
/* swap odd and even bits 1 bit*/
t = ((t & 0xAAAAAAAA) >> 1) | ((t & 0x55555555) << 1);
/* 2 bits */
t = ((t & 0xCCCCCCCC) >> 2) | ((t & 0x33333333) << 2);
/* 4 bits */
t = ((t & 0xF0F0F0F0) >> 4) | ((t & 0x0F0F0F0F) << 4);
/* 8 bits */
t = ((t & 0xFF00FF00) >> 8) | ((t & 0x00FF00FF) << 8);
/* 16 bits */
t = ((t & 0xFFFF0000) >> 16) | ((t & 0x0000FFFF) << 16);
return t;
}
/* simplification of reverseBits_2 */
uint32_t reverseBits(uint32_t n) {
n = ((n >> 1) & 0x55555555) | ((n & 0x55555555) << 1);
n = ((n >> 2) & 0x33333333) | ((n & 0x33333333) << 2);
n = ((n >> 4) & 0x0F0F0F0F) | ((n & 0x0F0F0F0F) << 4);
n = ((n >> 8) & 0x00FF00FF) | ((n & 0x00FF00FF) << 8);
n = ( n >> 16 ) | ( n << 16);
return n;
}
int main() {
uint32_t n = 2147483648;
printf("%u\n", reverseBits(n));
return 0;
}