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minimum-swaps-to-group-all-1s-together

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Given a binary array data, return the minimum number of swaps required to group all 1’s present in the array together in any place in the array.

 

Example 1:

Input: [1,0,1,0,1]
Output: 1
Explanation: 
There are 3 ways to group all 1's together:
[1,1,1,0,0] using 1 swap.
[0,1,1,1,0] using 2 swaps.
[0,0,1,1,1] using 1 swap.
The minimum is 1.

Example 2:

Input: [0,0,0,1,0]
Output: 0
Explanation: 
Since there is only one 1 in the array, no swaps needed.

Example 3:

Input: [1,0,1,0,1,0,0,1,1,0,1]
Output: 3
Explanation: 
One possible solution that uses 3 swaps is [0,0,0,0,0,1,1,1,1,1,1].

 

Note:

  1. 1 <= data.length <= 10^5
  2. 0 <= data[i] <= 1

Related Topics

[Array] [Sliding Window]

Hints

Hint 1 How many 1's should be grouped together ? Is not a fixed number?
Hint 2 Yeah it's just the number of 1's the whole array has. Let's name this number as ones
Hint 3 Every subarray of size of ones, needs some number of swaps to reach, Can you find the number of swaps needed to group all 1's in this subarray?
Hint 4 It's the number of zeros in that subarray.
Hint 5 Do you need to count the number of zeros all over again for every position ?
Hint 6 Use Sliding Window technique.