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i^i returns i instead of e^(-pi/2) #656

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SomebodyLikeEveryBody opened this issue Jan 27, 2022 · 0 comments
Open

i^i returns i instead of e^(-pi/2) #656

SomebodyLikeEveryBody opened this issue Jan 27, 2022 · 0 comments

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@SomebodyLikeEveryBody
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When we do

nerdamer('i^i').toString()

it returns

i

instead of

e^(-pi/2)

@SomebodyLikeEveryBody SomebodyLikeEveryBody changed the title i^i returns i instead of -i i^i returns i instead of e^(-pi/2) Jan 27, 2022
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