From 4cc375b77ccf1e228d919ea8e65788161b05bf95 Mon Sep 17 00:00:00 2001
From: Jose <jesparza@enjoty.com>
Date: Sun, 1 May 2016 19:44:46 +0200
Subject: [PATCH] PEP8 changes in PDFCrypto

---
 PDFCrypto.py | 22 ++++++++++++++--------
 peepdf.py    |  2 +-
 2 files changed, 15 insertions(+), 9 deletions(-)

diff --git a/PDFCrypto.py b/PDFCrypto.py
index f01d2c2..e16e345 100644
--- a/PDFCrypto.py
+++ b/PDFCrypto.py
@@ -31,6 +31,7 @@
 
 paddingString = '\x28\xBF\x4E\x5E\x4E\x75\x8A\x41\x64\x00\x4E\x56\xFF\xFA\x01\x08\x2E\x2E\x00\xB6\xD0\x68\x3E\x80\x2F\x0C\xA9\xFE\x64\x53\x69\x7A'
 
+
 def computeEncryptionKey(password, dictOwnerPass, dictUserPass, dictOE, dictUE, fileID, pElement, dictKeyLength = 128, revision = 3, encryptMetadata = False, passwordType = None):
     '''
         Compute an encryption key to encrypt/decrypt the PDF file
@@ -84,6 +85,7 @@ def computeEncryptionKey(password, dictOwnerPass, dictUserPass, dictOE, dictUE,
     except:
         return (-1, 'ComputeEncryptionKey error: %s %s' % (str(sys.exc_info()[0]),str(sys.exc_info()[1])))
 
+
 def computeObjectKey(id, generationNum, encryptionKey, keyLengthBytes, algorithm = 'RC4'):
     '''
         Compute the key necessary to encrypt each object, depending on the id and generation number. Only necessary with /V < 5.
@@ -109,6 +111,7 @@ def computeObjectKey(id, generationNum, encryptionKey, keyLengthBytes, algorithm
     except:
         return (-1, 'ComputeObjectKey error: %s %s' % (str(sys.exc_info()[0]),str(sys.exc_info()[1])))
 
+
 def computeOwnerPass(ownerPassString, userPassString, keyLength = 128, revision = 3):
     '''
         Compute the owner password necessary to compute the encryption key of the PDF file
@@ -152,6 +155,7 @@ def computeOwnerPass(ownerPassString, userPassString, keyLength = 128, revision
     except:
         return (-1, 'ComputeOwnerPass error: %s %s' % (str(sys.exc_info()[0]),str(sys.exc_info()[1])))
 
+
 def computeUserPass(userPassString, dictO, fileID, pElement, keyLength = 128, revision = 3, encryptMetadata = False):
     '''
         Compute the user password of the PDF file
@@ -277,7 +281,8 @@ def isOwnerPass(password, dictO, dictU, computedUserPass, keyLength, revision):
             # Is it possible??
             userPass = ''
         return isUserPass(userPass, computedUserPass, dictU, revision)
-    
+
+
 def RC4(data, key):
     '''
         RC4 implementation
@@ -296,24 +301,25 @@ def RC4(data, key):
     #Initialization
     for x in range(256):
         hash[x] = ord(key[x % keyLength])
-        box[x]    = x  
+        box[x] = x
     for x in range(256):
-        y            = (y + int(box[x]) + int(hash[x])) % 256 
-        tmp        = box[x]
+        y = (y + int(box[x]) + int(hash[x])) % 256
+        tmp = box[x]
         box[x] = box[y]
         box[y] = tmp 
 
     z = y = 0
-    for x in range(0,dataLength):
+    for x in range(0, dataLength):
         z = (z + 1) % 256 
         y = (y + box[z]) % 256
-        tmp    = box[z]
+        tmp = box[z]
         box[z] = box[y]
         box[y] = tmp
-        k    = box[((box[z] + box[y]) % 256)]
-        ret    += chr(ord(data[x]) ^ k)
+        k = box[((box[z] + box[y]) % 256)]
+        ret += chr(ord(data[x]) ^ k)
     return ret
 
+
 '''
     Author: Evan Fosmark (http://www.evanfosmark.com/2008/06/xor-encryption-with-python/)
 '''
diff --git a/peepdf.py b/peepdf.py
index 40faa68..675c627 100755
--- a/peepdf.py
+++ b/peepdf.py
@@ -362,7 +362,7 @@ def getPeepJSON(statsDict, version, revision):
 twitter = 'http://twitter.com/EternalTodo'
 peepTwitter = 'http://twitter.com/peepdf'
 version = '0.3'
-revision = '271'
+revision = '272'
 stats = ''
 pdf = None
 fileName = None