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when l2 isn't running, l1 runs straight down and ends up breaking its chain. so, check whether or not l2 has current; or check l2's encoder. If l2 is in an appropriate position, then move l1
(Tim's idea)
The text was updated successfully, but these errors were encountered:
when l2 isn't running, l1 runs straight down and ends up breaking its chain. so, check whether or not l2 has current; or check l2's encoder. If l2 is in an appropriate position, then move l1
(Tim's idea)
The text was updated successfully, but these errors were encountered: