LeetCode #: 72
Difficulty: Hard
Topic: String, Dynamic Programming.
Given two words word1
and word2
, find the minimum number of operations required to convert word1
to word2
.
You have the following 3 operations permitted on a word:
Insert a character Delete a character Replace a character
Example 1:
Input: word1 = "horse", word2 = "ros"
Output: 3
Explanation:
horse -> rorse (replace 'h' with 'r')
rorse -> rose (remove 'r')
rose -> ros (remove 'e')
Example 2:
Input: word1 = "intention", word2 = "execution"
Output: 5
Explanation:
intention -> inention (remove 't')
inention -> enention (replace 'i' with 'e')
enention -> exention (replace 'n' with 'x')
exention -> exection (replace 'n' with 'c')
exection -> execution (insert 'u')
The idea here is to use a (m+1)*(n+1)
matrix where rows represent characters in word1
and columns represent characters in word2
. Each cell represent the number of operations required to change word1[0..i]
to word2[0..j]
.
In the end, the result would be dp[i][j]
.
Reference: C++ O(n)-space DP by jianchao-li.
Assume m is the length of word1
and n is the length of word2
.
Time complexity: O(m*n)
Space complexity: O(m*n)