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WhereClause.noneOf()

David Fahlander edited this page Feb 24, 2016 · 11 revisions

Syntax

table.where(indexOrPrimKey).noneOf([key1, key2, keyN, ...])

Parameters

indexOrPrimKey: String Name of an index or primary key registered in Version.stores()
key Array of keys to compare with. Each key MUST be a Number, String, Date or Array instance. Booleans are not accepted as valid keys

Return Value

Collection or WriteableCollection depending on table type

Remarks

Queries the collection for all valid values that does not match given value. Note that you will only find values that are valid indexedDB keys.

Given the following data:

{ id: 1, shoeSize: 9 }
{ id: 2, shoeSize: 10 }
{ id: 3, shoeSize: 11 }
{ id: 4 }
{ id: 5, shoeSize: null }
{ id: 6, shoeSize: "abc" }
{ id: 7, shoeSize: false }
{ id: 8, shoeSize: ["a","b","c"]}

And the following query:

db.people.where('shoeSize').noneOf([10,11]).each(function(x) {
    console.log("Found: + JSON.stringify(x));
});

We get the following result:

Found: "{id:1,shoeSize:9}"
Found: "{id:6,shoeSize:\"abc\"}"
Found: "{id:8,shoeSize:[\"a\",\"b\",\"c\"]}"

Note that only items where shoeSize points to a valid key will be included in the result. A valid key is a key of type string, number, Date or Array<string | number | Date>.

Practical Limitations

In Dexie version < 1.3.0, WhereClause.noneOf() will launch a parallell query for each item being searched for so it is not suited for looking for large sets.

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