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_297.java
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_297.java
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package com.fishercoder.solutions;
import com.fishercoder.common.classes.TreeNode;
import java.util.LinkedList;
import java.util.Queue;
/**
* 297. Serialize and Deserialize Binary Tree
*
* Serialization is the process of converting a data structure or object into a sequence of bits
* so that it can be stored in a file or memory buffer,
* or transmitted across a network connection link to be reconstructed later in the same or another computer environment.
* Design an algorithm to serialize and deserialize a binary tree.
* There is no restriction on how your serialization/deserialization algorithm should work.
* You just need to ensure that a binary tree can be serialized to a string and this string can
* be deserialized to the original tree structure.
For example, you may serialize the following tree
1
/ \
2 3
/ \
4 5
as "[1,2,3,null,null,4,5]",
just the same as how LeetCode OJ serializes a binary tree.
You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself.
Note: Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.
*/
public class _297 {
/**The idea is very straightforward:
use "#" as the terminator, do BFS, level order traversal to store all nodes values into a StringBuilder.
When deserializing, also use a queue: pop the root into the queue first, then use a for loop to construct each node,
then eventually just return the root.
*/
// Encodes a tree to a single string.
public String serialize(TreeNode root) {
if (root == null) {
return "";
}
StringBuilder sb = new StringBuilder();
Queue<TreeNode> queue = new LinkedList();
queue.offer(root);
while (!queue.isEmpty()) {
int size = queue.size();
for (int i = 0; i < size; i++) {
TreeNode curr = queue.poll();
if (curr == null) {
sb.append("# ");
continue;
}
sb.append(curr.val);
sb.append(" ");
queue.offer(curr.left);
queue.offer(curr.right);
}
}
return sb.toString();
}
// Decodes your encoded data to tree.
public TreeNode deserialize(String data) {
if (data == null || data.isEmpty()) {
return null;
}
String[] nodes = data.split(" ");
TreeNode root = new TreeNode(Integer.valueOf(nodes[0]));
Queue<TreeNode> queue = new LinkedList();
queue.offer(root);
for (int i = 1; i < nodes.length; i++) {
TreeNode curr = queue.poll();
if (!nodes[i].equals("#")) {
curr.left = new TreeNode(Integer.valueOf(nodes[i]));
queue.offer(curr.left);
}
if (!nodes[++i].equals("#")) {
curr.right = new TreeNode(Integer.valueOf(nodes[i]));
queue.offer(curr.right);
}
}
return root;
}
}