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_890.java
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_890.java
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package com.fishercoder.solutions;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.HashSet;
import java.util.List;
import java.util.Map;
import java.util.Set;
/**
* 890. Find and Replace Pattern
*
* You have a list of words and a pattern, and you want to know which words in words matches the pattern.
* A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the desired word.
* (Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter.)
* Return a list of the words in words that match the given pattern.
* You may return the answer in any order.
*
* Example 1:
*
* Input: words = ["abc","deq","mee","aqq","dkd","ccc"], pattern = "abb"
* Output: ["mee","aqq"]
* Explanation: "mee" matches the pattern because there is a permutation {a -> m, b -> e, ...}.
* "ccc" does not match the pattern because {a -> c, b -> c, ...} is not a permutation,
* since a and b map to the same letter.
*
* Note:
* 1 <= words.length <= 50
* 1 <= pattern.length = words[i].length <= 20
*/
public class _890 {
public static class Solution1 {
public List<String> findAndReplacePattern(String[] words, String pattern) {
List<String> result = new ArrayList<>();
for (String word : words) {
Map<Character, Character> map = new HashMap<>();
Set<Character> set = new HashSet<>();
boolean match = true;
for (int i = 0; i < pattern.length(); i++) {
if (map.containsKey(pattern.charAt(i))) {
if (word.charAt(i) != map.get(pattern.charAt(i))) {
match = false;
break;
}
} else {
map.put(pattern.charAt(i), word.charAt(i));
if (!set.add(word.charAt(i))) {
match = false;
}
}
}
if (match) {
result.add(word);
}
}
return result;
}
}
}