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_605.java
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_605.java
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package com.fishercoder.solutions;
/**
* 605. Can Place Flowers
*
* Suppose you have a long flowerbed in which some of the plots are planted and some are not.
* However, flowers cannot be planted in adjacent plots - they would compete for water and both would die.
Given a flowerbed (represented as an array containing 0 and 1, where 0 means empty and 1 means not empty),
and a number n, return if n new flowers can be planted in it without violating the no-adjacent-flowers rule.
Example 1:
Input: flowerbed = [1,0,0,0,1], n = 1
Output: True
Example 2:
Input: flowerbed = [1,0,0,0,1], n = 2
Output: False
Note:
The input array won't violate no-adjacent-flowers rule.
The input array size is in the range of [1, 20000].
n is a non-negative integer which won't exceed the input array size.
*/
public class _605 {
public static class Solution1 {
public boolean canPlaceFlowers(int[] flowerbed, int n) {
int count = 0;
int i = 0;
while (i < flowerbed.length) {
if (flowerbed[i] == 0 && (i == 0 || flowerbed[i - 1] == 0) && (i == flowerbed.length - 1 || flowerbed[i + 1] == 0)) {
count++;
flowerbed[i] = 1;
}
if (count >= n) {
return true;
}
i++;
}
if (count >= n) {
return true;
}
return false;
}
}
public static class Solution2 {
public boolean canPlaceFlowers(int[] flowerbed, int n) {
int len = flowerbed.length;
if (len == 1) {
if ((flowerbed[0] == 0 && n <= 1) || n == 0) {
return true;
}
return false;
}
if (flowerbed[0] == 0 && flowerbed[1] == 0) {
flowerbed[0] = 1;
n--;
}
for (int i = 1; i < len - 1; i++) {
if (flowerbed[i] == 0 && flowerbed[i - 1] == 0 && flowerbed[i + 1] == 0) {
n--;
flowerbed[i] = 1;//modify the input, discuss this with interviwer, if not allowed, then have a copy of this input and modify copy
}
if (n <= 0) {
return true;
}
}
if (len >= 2 && flowerbed[len - 2] == 0 && flowerbed[len - 1] == 0) {
n--;
}
if (n <= 0) {
return true;
}
return false;
}
}
}