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_496.java
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_496.java
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package com.fishercoder.solutions;
import java.util.HashMap;
import java.util.Map;
import java.util.Stack;
/**
* 496. Next Greater Element I
*
* You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2.
* Find all the next greater numbers for nums1's elements in the corresponding places of nums2.
* The Next Greater Number of a number x in nums1 is the first greater number to its right in nums2. If it does not exist, output -1 for this number.
Example 1:
Input: nums1 = [4,1,2], nums2 = [1,3,4,2].
Output: [-1,3,-1]
Explanation:
For number 4 in the first array, you cannot find the next greater number for it in the second array, so output -1.
For number 1 in the first array, the next greater number for it in the second array is 3.
For number 2 in the first array, there is no next greater number for it in the second array, so output -1.
Example 2:
Input: nums1 = [2,4], nums2 = [1,2,3,4].
Output: [3,-1]
Explanation:
For number 2 in the first array, the next greater number for it in the second array is 3.
For number 4 in the first array, there is no next greater number for it in the second array, so output -1.
Note:
All elements in nums1 and nums2 are unique.
The length of both nums1 and nums2 would not exceed 1000.
*/
public class _496 {
public static class Solution1 {
public int[] nextGreaterElement(int[] findNums, int[] nums) {
Stack<Integer> stack = new Stack();
Map<Integer, Integer> map = new HashMap();
for (int i = 0; i < nums.length; i++) {
while (!stack.isEmpty() && nums[i] > stack.peek()) {
map.put(stack.pop(), nums[i]);
}
stack.push(nums[i]);
}
while (!stack.isEmpty()) {
map.put(stack.pop(), -1);
}
int[] result = new int[findNums.length];
for (int i = 0; i < findNums.length; i++) {
result[i] = map.get(findNums[i]);
}
return result;
}
}
}