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Unable to use a custom prior that contains a pm.Deterministic
#857
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Hey @ivanistheone thanks for the detailed issue. I think this is the expected behavior as deterministic variables are components in probabilistic programming that represent values that are completely determined by their input variables. A deterministic prior cannot be sampled directly as these deterministic variables are computed based on their parent variables rather than being sampled like traditional random variables. @tomicapretto correct me if I am wrong here. |
Right. From reading other code examples (PyMC) I see them always used as extra computed variables, but never to specify priors. Is there another way to produce a custom prior of the form Here is another thing I tried based on def ShiftedExpCustomDist(name, lam, **kwargs):
def shited_exp(lam, loc, size):
return pm.Exponential.dist(lam=lam) + loc
return pm.CustomDist(name, lam, 1, dist=shited_exp, **kwargs)
priorscd = {
...
"nu": bmb.Prior("ShiftedExpCustomDist", lam=1/29, dist=ShiftedExpCustomDist),
} which seems to work, though it produced a lot of divergent transitions, so its probably not the right way to do this. |
Yeah, this code follows a lot more closely with what the PyMC docs recommend. See the third example here for an example of a shifted exponential distribution. I you pass import pymc as pm
from pytensor.tensor import TensorVariable
def dist(
lam: TensorVariable,
shift: TensorVariable,
size: TensorVariable,
) -> TensorVariable:
return pm.Exponential.dist(lam, size=size) + shift
iqs_mean, iqs_std = iqs["iq"].mean(), iqs["iq"].std()
formula = bmb.Formula("iq ~ 0 + group", "sigma ~ 0 + group")
priors = {
"group": bmb.Prior("Normal", mu=iqs_mean, sigma=1000*iqs_std),
"sigma": {"group": bmb.Prior("Uniform", lower=np.log(iqs_std/1000), upper=np.log(iqs_std*1000))},
"nu": bmb.Prior(
"ShiftedExponential",
lam=1/29,
shift=-1.0,
dist=lambda name, lam, shift: pm.CustomDist(
name,
lam,
shift,
dist=dist,
signature="(),()->()"
)
)
} |
That makes sense since I passed I will keep the issue open and add a docs tag to remember to add an example on using |
Hello! I'm trying to reproduce the model from the Bayesian Estimation Supersedes the t-Test paper in Bambi.
I would like to set a "shifted exponential" for the degrees of freedom parameter$\nu \sim \text{Expon}\left(\lambda=\frac{1}{29}\right) + 1$ , which is what we would get if the pm.Exponential accepted the
loc=1
option likescipy.stats.expon
.I tried implementing the shifted exponential using a custom prior:
the model builds and graphs fine
but when I run
model.fit()
I get the following error:ValueError: Random variables detected in the logp graph: {MeasurableAdd.0, exponential_rv{"()->()"}.out}.
This can happen when DensityDist logp or Interval transform functions reference nonlocal variables,
or when not all rvs have a corresponding value variable.
with traceback
Complete code example below the fold
Workaround using pm.Truncated
In this specific case, I found a workaround using$\text{Expon}\left(\lambda=\frac{1}{29}\right)$ it starting at 1, gives the same PDF as $\text{Expon}\left(\lambda=\frac{1}{29}\right) + 1$ , as shown below:
pm.Truncated
, since the exponential function is self-similar, so truncatingI still wanted to flag
Deterministic
didn't work---or what is more likely---I'm not using it right.See this notebook for complete code:
https://github.com/minireference/noBSstats/blob/main/notebooks/explorations/bambi_BEST_Deterministic.ipynb
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