-
Notifications
You must be signed in to change notification settings - Fork 243
/
Mirror.cpp
79 lines (61 loc) · 1.74 KB
/
Mirror.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
/*
Mirror
For a given Binary Tree of type integer, update it with its corresponding mirror image.
Example:
1 1
/ \ / \
2 3 -----> 3 2
/ \ / \ / \ / \
4 5 6 7 7 6 5 4
Input Format:
The first and the only line of input will contain the node data, all separated by a single space. Since -1 is used as an indication whether the left or
right node data exist for root, it will not be a part of the node data.
Output Format:
The only line of output prints the mirrored tree in a level-wise order.
Each level will be printed on a new line. Elements printed at each level will be separated by a single line.
Note:
You are not required to print anything explicitly. It has already been taken care of.
Constraints:
1 <= N <= 10^5
Where N is the total number of nodes in the binary tree.
Time Limit: 1 sec
Sample Input 1:
1 2 3 4 5 6 7 -1 -1 -1 -1 -1 -1 -1 -1
Sample Output 1:
1
3 2
7 6 5 4
Sample Input 2:
5 10 6 2 3 -1 -1 -1 -1 -1 9 -1 -1
Sample Output 2:
5
6 10
3 2
9
*/
/**********************************************************
Following is the Binary Tree Node class structure
template <typename T>
class BinaryTreeNode {
public :
T data;
BinaryTreeNode<T> *left;
BinaryTreeNode<T> *right;
BinaryTreeNode(T data) {
this -> data = data;
left = NULL;
right = NULL;
}
};
*/
void mirrorBinaryTree(BinaryTreeNode<int>* root) {
// Write your code here
//corner case
if(root == NULL) {
return;
}
mirrorBinaryTree(root -> left);
mirrorBinaryTree(root -> right);
swap(root -> left, root -> right);
return;
}