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Is default release working? #2

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rfvermut opened this issue May 17, 2018 · 0 comments
Open

Is default release working? #2

rfvermut opened this issue May 17, 2018 · 0 comments

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@rfvermut
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I run it as said in README:

Then invoke:

logger -n localhost  -P 514 sdfsdfds -i foo

Result:

May 17 22:45:16 ip-10-10-11-150 rsyslog-journal[2607]: no message
May 17 22:45:16 ip-10-10-11-150 rsyslog-journald-repeater[2607]: K=proc_id, V=2827,                  Type=string
May 17 22:45:16 ip-10-10-11-150 rsyslog-journald-repeater[2607]: K=hostname, V=ip-10-10-11-150,                  Type=string
May 17 22:45:16 ip-10-10-11-150 rsyslog-journald-repeater[2607]: K=msg_id, V=-,                  Type=string
May 17 22:45:16 ip-10-10-11-150 rsyslog-journald-repeater[2607]: K=structured_data, V=[timeQuality tzKnown="1" isSynced="1" syncAccuracy="199500"],                  Type=string
May 17 22:45:16 ip-10-10-11-150 rsyslog-journald-repeater[2607]: K=priority, V=13,                  Type=int
May 17 22:45:16 ip-10-10-11-150 rsyslog-journald-repeater[2607]: K=facility, V=1,                  Type=int
May 17 22:45:16 ip-10-10-11-150 rsyslog-journald-repeater[2607]: K=severity, V=5,                  Type=int
May 17 22:45:16 ip-10-10-11-150 rsyslog-journald-repeater[2607]: K=version, V=1,                  Type=int
May 17 22:45:16 ip-10-10-11-150 rsyslog-journald-repeater[2607]: K=timestamp, V=2018-05-17 22:45:16.111812 +0000 UTC,                  Type=time.Time
May 17 22:45:16 ip-10-10-11-150 rsyslog-journald-repeater[2607]: K=message, V=sdfsdfds foo,                  Type=string
May 17 22:45:16 ip-10-10-11-150 rsyslog-journald-repeater[2607]: K=client, V=127.0.0.1:55048,                  Type=string
May 17 22:45:16 ip-10-10-11-150 rsyslog-journald-repeater[2607]: K=tls_peer, V=,                  Type=string

Somehow it logs no message even if it shows it in debug.

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