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prove that a pedersen commitment is to a value a<x<b.
If b-a is a power of 2 this can be done non interactively with only one range proof assuming the:
prover commits to a value a<x<b
prover generates a pedersen commitment to a value a
prover generates a range proof to commitment that is commitment from 1 minus commitment from 2
prover sends range proof together with the opening of the commitment from 2
The text was updated successfully, but these errors were encountered:
prove that a pedersen commitment is to a value
a<x<b
.If
b-a
is a power of 2 this can be done non interactively with only one range proof assuming the:a<x<b
a
The text was updated successfully, but these errors were encountered: