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09_linked_list_reverse.cpp
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09_linked_list_reverse.cpp
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/*
TOPIC: Reverse a Linked List
NOTE: We will be swapping the POINTER not the DATA to reverse a linked list.
As, Swapping data of nodes may be expensive in many situations when data contains many fields.
*/
#include <iostream>
using namespace std;
class Node{
public:
int data;
Node *next;
// constructor
Node(int d)
{
data = d;
next = NULL;
}
};
// pass a pointer by reference (because we want to make changes to the original head pointer)
void insertAtHead(Node *&head, int d)
{
if(head == NULL)
{
head = new Node(d);
return;
}
Node *n = new Node(d);
n->next = head;
head = n;
}
// function to find length of linked list
int length(Node*head)
{
int cnt = 0;
while(head != NULL)
{
cnt++;
head = head->next;
}
return cnt;
}
// function to insert data at last position of linked list
void insertAtTail(Node*&head, int data)
{
// corner case
if(head == NULL)
{
// Node *n = new Node(data);
// head = n;
head = new Node(data);
return;
}
Node *tail = head; // using temp pointer
// Moving head towards tail
while(tail->next != NULL)
{
tail = tail->next;
}
// create & attach new node
tail->next = new Node(data);
}
// function to insert data at middle of linked list
void insertAtMiddle(Node*&head, int data, int pos)
{
//corner case
if(head==NULL or pos==0)
{
insertAtHead(head, data);
return;
}
else if (pos >= length(head))
{
insertAtTail(head, data);
return;
}
// take pos-1 jumps
int i=1;
Node *temp = head;
while(i < pos)
{
temp = temp->next;
i++;
}
// create a new node
Node *n = new Node(data);
n->next = temp->next;
temp->next = n;
}
// pass by value (because we don't want to change the original head pointer)
void print(Node *head)
{
while(head != NULL)
{
cout << head->data << " -> ";
head = head->next;
}
cout << endl;
}
// function to delete data at start of linked list
void deleteAtHead(Node*&head)
{
if(head == NULL)
{
return;
}
Node*temp = head->next; // temp pointer is static. So it will be deleted at the end of function call
delete head; // delete the Node whose address is stored in "head" pointer
head = temp;
}
// function to delete data at end of linked list
void deleteAtTail(Node*&head)
{
if(head == NULL)
{
return;
}
Node *tail = head;
Node *prev;
// moving towards the end of linked list
while(tail->next != NULL)
{
prev = tail;
tail = tail->next;
}
delete tail; // delete the Node whose address is stored in "tail" pointer
// delete prev->next; // prev->nex & tail are pointing towards same address
prev->next = NULL;
}
// function to delete data at end of linked list
void deleteAtMiddle(Node*&head, int pos)
{
if(head==NULL)
{
return;
}
else if(pos >= length(head))
{
return;
}
// jump towards pos
Node *temp = head;
Node *prev;
int i = 1;
while(i <= pos)
{
prev = temp;
temp = temp->next;
i++;
}
prev->next = temp->next;
delete temp; // delete the Node whose address is stored in "temp" pointer
}
// Search Operation
// Linear Search
bool search(Node*head, int key)
{
Node*temp = head;
while(temp != NULL)
{
if(temp->data == key)
{
return true;
}
temp = temp->next;
}
// if key not found
return false;
}
// Linear Search (recursively)
bool searchRecursive(Node*head, int key)
{
//base case
if(head == NULL)
{
return false;
}
//rec case
if(head->data == key)
{
return true;
}
return searchRecursive(head->next, key);
}
// Linked List User Input
void take_input(Node*&head)
{
//
}
// Linked List User Input
Node* take_input_2()
{
Node *head = NULL;
int data;
cin >> data;
while(data != -1)
{
insertAtHead(head, data);
// insertAtTail(head, data);
cin >> data;
}
return head;
/* NOTE: Since we are adding elements at "head" of linked list.
So, we will be getting linked list in the reverse order.
*/
}
// Linked List User Input [When taking Input from a file]
Node* take_input_file()
{
Node *head = NULL;
int data;
// cin >> data;
while(cin >> data)
// while(data != -1)
{
insertAtHead(head, data);
// cin >> data;
}
return head;
/* NOTE: Since we are adding elements at "head" of linked list.
So, we will be getting linked list in the reverse order.
*/
}
/*
- Using "<<" for getting output
Eg: cout << head;
This will print the address of head.
But we want to print entire linked list uing "cout".
So, we will use operator overloading.
NOTE: cout << head;
| |
ostream Node
object object
So, "<<" operator will take 2 parameter.
One is Ostream object (for "cout")
Second is Node object (for "head")
*/
// // Opertor Overloading (i.e for cases like: cout << head;)
// void operator<<(ostream &os, Node *head)
// {
// print(head);
// return;
// }
// Cascading of Operators (i.e for cases like: cout << head << head2;)
ostream& operator<<(ostream &os, Node *head) // Both Return & Pass are by Reference
{
print(head);
return os; // returning "cout" by reference
/*
=> cout << head << head2;
|-----------|
return cout
=> cout << head2;
|------------|
return cout
=> cout; [OUTPUT]
NOTE: We will get "cout; as output.
"cout;" is a valid statement in C++ & writing it doesnot do anything.
*/
}
// Cascading of Operators (i.e for cases like: cin >> head >> head2;)
istream& operator>>(istream &is, Node *&head)
{
head = take_input_2();
return is;
}
// reverse a linked list
void reverse(Node *&head)
{
Node *curr = head; // for current node
Node *prev = NULL; // for previous node
Node *nxt; // for next node
while(curr != NULL)
{
nxt = curr->next; // save the next node
curr->next = prev; // make the current node point to previous node
prev = curr; // update previous node (for the next iteration)
curr = nxt; // update current node (for the next iteration)
}
head = prev; // update head
}
int main()
{
Node *head = NULL;
cout << "Enter Elements [Press -1 to Exit]: ";
cin >> head;
cout << "Linked List: ";
// print(head);
cout << head;
reverse(head); // reverse the linked list
cout << "Linked List [After Reversed]: ";
cout << head;
return 0;
}
/*
OUTPUT:
Enter Elements [Press -1 to Exit] : 19 4 37 5 9 -1
Linked List : 9 -> 5 -> 37 -> 4 -> 19
Linked List [After Reversed] : 19 -> 4 -> 37 -> 5 -> 9
*/