CompletableFuture 提供了四个静态方法来创建一个异步操作。
public static CompletableFuture<Void> runAsync(Runnable runnable)
public static CompletableFuture<Void> runAsync(Runnable runnable, Executor executor)
public static <U> CompletableFuture<U> supplyAsync(Supplier<U> supplier)
public static <U> CompletableFuture<U> supplyAsync(Supplier<U> supplier, Executor executor)
没有指定Executor的方法会使用ForkJoinPool.commonPool() 作为它的线程池执行异步代码。如果指定线程池,则使用指定的线程池运行。以下所有的方法都类同。
- runAsync方法不支持返回值。
- supplyAsync可以支持返回值。
示例:
//无返回值
private static void runAsync() throws Exception {
CompletableFuture<Void> future = CompletableFuture.runAsync(() -> {
try {
TimeUnit.SECONDS.sleep(1);
} catch (InterruptedException e) {
}
System.out.println("run end ...");
});
future.get();
}
//有返回值
private static void supplyAsync() throws Exception {
CompletableFuture<Long> future = CompletableFuture.supplyAsync(() -> {
try {
TimeUnit.SECONDS.sleep(1);
} catch (InterruptedException e) {
}
System.out.println("run end ...");
return System.currentTimeMillis();
});
long time = future.get();
System.out.println("time = "+time);
}
以下4个方法用于获取结果
//同步获取结果
public T get()
public T get(long timeout, TimeUnit unit)
public T getNow(T valueIfAbsent)
public T join()
getNow
有点特殊,如果结果已经计算完则返回结果或者抛出异常,否则返回给定的valueIfAbsent值。join()
与get()
区别在于join()
返回计算的结果或者抛出一个unchecked异常(CompletionException),而get()
返回一个具体的异常。
当CompletableFuture的计算结果完成,或者抛出异常的时候,可以执行特定的Action。主要是下面的方法:
public CompletableFuture<T> whenComplete(BiConsumer<? super T,? super Throwable> action)
public CompletableFuture<T> whenCompleteAsync(BiConsumer<? super T,? super Throwable> action)
public CompletableFuture<T> whenCompleteAsync(BiConsumer<? super T,? super Throwable> action, Executor executor)
public CompletableFuture<T> exceptionally(Function<Throwable,? extends T> fn)
可以看到Action的类型是BiConsumer<? super T,? super Throwable>它可以处理正常的计算结果,或者异常情况。
whenComplete 和 whenCompleteAsync 的区别:
- whenComplete:是执行当前任务的线程执行继续执行 whenComplete 的任务。
- whenCompleteAsync:是执行把 whenCompleteAsync 这个任务继续提交给线程池来进行执行。
示例:
private static void whenComplete() throws Exception {
CompletableFuture<Void> future = CompletableFuture.runAsync(() -> {
try {
TimeUnit.SECONDS.sleep(1);
} catch (InterruptedException e) {
}
if(new Random().nextInt()%2>=0) {
int i = 12/0;
}
System.out.println("run end ...");
});
future.whenComplete((t, action) -> System.out.println("执行完成!"));
future.exceptionally(t -> {
System.out.println("执行失败!"+t.getMessage());
return null;
});
TimeUnit.SECONDS.sleep(2);
}
当一个线程依赖另一个线程时,可以使用 thenApply 方法来把这两个线程串行化。
public <U> CompletableFuture<U> thenApply(Function<? super T,? extends U> fn)
public <U> CompletableFuture<U> thenApplyAsync(Function<? super T,? extends U> fn)
public <U> CompletableFuture<U> thenApplyAsync(Function<? super T,? extends U> fn, Executor executor)
Function<? super T,? extends U>
- T:上一个任务返回结果的类型
- U:当前任务的返回值类型
示例:
private static void thenApply() throws Exception {
CompletableFuture<Long> future = CompletableFuture.supplyAsync(() -> {
long result = new Random().nextInt(100);
System.out.println("result1=" + result);
return result;
}).thenApply(t -> {
long result = t * 5;
System.out.println("result2=" + result);
return result;
});
long result = future.get();
System.out.println(result);
}
第二个任务依赖第一个任务的结果。
handle 是执行任务完成时对结果的处理。 handle 方法和 thenApply 方法处理方式基本一样。不同的是 handle 是在任务完成后再执行,还可以处理异常的任务。thenApply 只可以执行正常的任务,任务出现异常则不执行 thenApply 方法。
public <U> CompletionStage<U> handle(BiFunction<? super T, Throwable, ? extends U> fn);
public <U> CompletionStage<U> handleAsync(BiFunction<? super T, Throwable, ? extends U> fn);
public <U> CompletionStage<U> handleAsync(BiFunction<? super T, Throwable, ? extends U> fn,Executor executor);
示例:
private static void handle() throws Exception{
CompletableFuture<Integer> future = CompletableFuture.supplyAsync(() -> {
int i= 10/0;
return new Random().nextInt(10);
}).handle((param, throwable) -> {
int result = -1;
if(throwable==null){
result = param * 2;
}else{
System.out.println(throwable.getMessage());
}
return result;
});
System.out.println(future.get());
}
从示例中可以看出,在 handle 中可以根据任务是否有异常来进行做相应的后续处理操作。==而 thenApply 方法,如果上个任务出现错误,则不会执行 thenApply 方法。==
接收任务的处理结果,并消费处理,无返回结果。
public CompletionStage<Void> thenAccept(Consumer<? super T> action);
public CompletionStage<Void> thenAcceptAsync(Consumer<? super T> action);
public CompletionStage<Void> thenAcceptAsync(Consumer<? super T> action,Executor executor);
示例:
private static void thenAccept() throws Exception{
CompletableFuture.supplyAsync(() -> new Random().nextInt(10))
.thenAccept(System.out::println);
}
从示例代码中可以看出,该方法只是消费执行完成的任务,并可以根据上面的任务返回的结果进行处理。并没有后续的输错操作。
跟 thenAccept 方法不一样的是,不关心任务的处理结果。只要上面的任务执行完成,就开始执行 thenAccept 。
public CompletionStage<Void> thenRun(Runnable action);
public CompletionStage<Void> thenRunAsync(Runnable action);
public CompletionStage<Void> thenRunAsync(Runnable action,Executor executor);
示例:
private static void thenRun() throws Exception{
CompletableFuture<Void> future = CompletableFuture.supplyAsync(() -> new Random().nextInt(10)).thenRun(() -> {
System.out.println("thenRun ...");
});
future.get();
}
该方法同 thenAccept 方法类似。不同的是上个任务处理完成后,并不会把计算的结果传给 thenRun 方法。只是处理完任务后,执行 thenAccept 的后续操作。
thenCombine 会把 两个 CompletionStage 的任务都执行完成后,把两个任务的结果一块交给 thenCombine 来处理。
public <U,V> CompletionStage<V> thenCombine(CompletionStage<? extends U> other,BiFunction<? super T,? super U,? extends V> fn);
public <U,V> CompletionStage<V> thenCombineAsync(CompletionStage<? extends U> other,BiFunction<? super T,? super U,? extends V> fn);
public <U,V> CompletionStage<V> thenCombineAsync(CompletionStage<? extends U> other,BiFunction<? super T,? super U,? extends V> fn,Executor executor);
示例:
private static void thenCombine() throws Exception {
CompletableFuture<String> future1 = CompletableFuture.supplyAsync(() -> "hello");
CompletableFuture<String> future2 = CompletableFuture.supplyAsync(() -> "hello");
CompletableFuture<String> result = future1.thenCombine(future2, (t, u) -> t+" "+u);
System.out.println(result.get());
}
当两个CompletionStage都执行完成后,把结果一块交给thenAcceptBoth来进行消耗
public <U> CompletionStage<Void> thenAcceptBoth(CompletionStage<? extends U> other,BiConsumer<? super T, ? super U> action);
public <U> CompletionStage<Void> thenAcceptBothAsync(CompletionStage<? extends U> other,BiConsumer<? super T, ? super U> action);
public <U> CompletionStage<Void> thenAcceptBothAsync(CompletionStage<? extends U> other,BiConsumer<? super T, ? super U> action, Executor executor);
示例:
private static void thenAcceptBoth() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(() -> {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(() -> {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
});
f1.thenAcceptBoth(f2, (t, u) -> System.out.println("f1="+t+";f2="+u+";"));
}
两个CompletionStage,谁执行返回的结果快,我就用那个CompletionStage的结果进行下一步的转化操作。
public <U> CompletionStage<U> applyToEither(CompletionStage<? extends T> other,Function<? super T, U> fn);
public <U> CompletionStage<U> applyToEitherAsync(CompletionStage<? extends T> other,Function<? super T, U> fn);
public <U> CompletionStage<U> applyToEitherAsync(CompletionStage<? extends T> other,Function<? super T, U> fn,Executor executor);
示例:
private static void applyToEither() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(() -> {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(() -> {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
});
CompletableFuture<Integer> result = f1.applyToEither(f2, t -> {
System.out.println(t);
return t * 2;
});
System.out.println(result.get());
}
两个CompletionStage,谁执行返回的结果快,我就用那个CompletionStage的结果进行下一步的消耗操作。
public CompletionStage<Void> acceptEither(CompletionStage<? extends T> other,Consumer<? super T> action);
public CompletionStage<Void> acceptEitherAsync(CompletionStage<? extends T> other,Consumer<? super T> action);
public CompletionStage<Void> acceptEitherAsync(CompletionStage<? extends T> other,Consumer<? super T> action,Executor executor);
示例:
private static void acceptEither() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(() -> {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(() -> {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
});
f1.acceptEither(f2, t -> System.out.println(t));
}
两个CompletionStage,任何一个完成了都会执行下一步的操作(Runnable)
public CompletionStage<Void> runAfterEither(CompletionStage<?> other,Runnable action);
public CompletionStage<Void> runAfterEitherAsync(CompletionStage<?> other,Runnable action);
public CompletionStage<Void> runAfterEitherAsync(CompletionStage<?> other,Runnable action,Executor executor);
示例:
private static void runAfterEither() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(() -> {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(() -> {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
});
f1.runAfterEither(f2, () -> System.out.println("上面有一个已经完成了。"));
}
两个CompletionStage,都完成了计算才会执行下一步的操作(Runnable)
public CompletionStage<Void> runAfterBoth(CompletionStage<?> other,Runnable action);
public CompletionStage<Void> runAfterBothAsync(CompletionStage<?> other,Runnable action);
public CompletionStage<Void> runAfterBothAsync(CompletionStage<?> other,Runnable action,Executor executor);
示例:
private static void runAfterBoth() throws Exception {
CompletableFuture<Integer> f1 = CompletableFuture.supplyAsync(() -> {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f1="+t);
return t;
});
CompletableFuture<Integer> f2 = CompletableFuture.supplyAsync(() -> {
int t = new Random().nextInt(3);
try {
TimeUnit.SECONDS.sleep(t);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("f2="+t);
return t;
});
f1.runAfterBoth(f2, () -> System.out.println("上面两个任务都执行完成了。"));
}
thenCompose 方法允许你对两个 CompletionStage 进行流水线操作,第一个操作完成时,将其结果作为参数传递给第二个操作。
public <U> CompletableFuture<U> thenCompose(Function<? super T, ? extends CompletionStage<U>> fn);
public <U> CompletableFuture<U> thenComposeAsync(Function<? super T, ? extends CompletionStage<U>> fn) ;
public <U> CompletableFuture<U> thenComposeAsync(Function<? super T, ? extends CompletionStage<U>> fn, Executor executor) ;
示例:
private static void thenCompose() throws Exception {
CompletableFuture<Integer> f = CompletableFuture.supplyAsync(() -> {
int t = new Random().nextInt(3);
System.out.println("t1="+t);
return t;
}).thenCompose(param -> CompletableFuture.supplyAsync(() -> {
int t = param *2;
System.out.println("t2="+t);
return t;
}));
System.out.println("thenCompose result : "+f.get());
}
@Test
//多线程编程示例
public void t2() throws ExecutionException, InterruptedException {
List<Object> list = Collections.synchronizedList(new ArrayList<>());
ArrayList<CompletableFuture> taskList = new ArrayList<>();
for (int i = 0; i < 1000; i++) {
CompletableFuture<Integer> future = CompletableFuture.supplyAsync(() -> {
System.out.println(Thread.currentThread().getName());
int r = RandomUtil.randomInt(1, 10);
return r;
}).whenCompleteAsync((integer, throwable) -> {
System.out.println("随机数为:" + integer);
list.add(integer);
});
taskList.add(future);
}
CompletableFuture.allOf(taskList.toArray(new CompletableFuture[]{})).get();
System.out.println("结束");
}