From e7782962b7abb9a4be0785dc9217dac9ed2a9cd0 Mon Sep 17 00:00:00 2001 From: huihut Date: Thu, 12 Sep 2019 02:09:58 +0800 Subject: [PATCH] Update pack.cpp Your PR can't be compiled, I modified some code. 1. Added the definition of T 2. Added delete heap variables 3. packIterative and printT separate two functions to uncouple code --- Problems/KnapsackProblem/pack.cpp | 74 ++++++++++++++++++------------- 1 file changed, 44 insertions(+), 30 deletions(-) diff --git a/Problems/KnapsackProblem/pack.cpp b/Problems/KnapsackProblem/pack.cpp index fb751ec7..60f0d8b7 100644 --- a/Problems/KnapsackProblem/pack.cpp +++ b/Problems/KnapsackProblem/pack.cpp @@ -2,6 +2,8 @@ #include using namespace std; +int **T = NULL; // 存储背包问题表格的数组指针 + // 返回两个值的最大值 int max(int a, int b) { return (a > b) ? a : b; @@ -9,38 +11,22 @@ int max(int a, int b) { // 迭代法,能显示背包问题的表格 int packIterative(int n, int W, int *w, int *v) { + // 循环遍历n行 - int T[i+1][j+1]; - for (int i = 0; i <= n; ++i) { + for (int i = 1; i <= n; ++i) + { // 循环遍历W列 - for (int j = 0; j <= W; ++j) { - if (i == 0 || j == 0) { - T[i][j] = 0; - } + for (int j = 1; j <= W; ++j) + { //第i个物品能装下,则比较包括第i个物品和不包括第i个物品,取其最大值 - if ( w[i-1] <= j) { - T[i][j] = max(v[i-1] + T[i - 1][j - w[i]], T[i - 1][j]); - } + if (w[i] <= j) + T[i][j] = max(v[i] + T[i - 1][j - w[i]], T[i - 1][j]); + // 第i个物品不能装下,则递归装i-1个 - else { + else T[i][j] = T[i - 1][j]; - } } } - - for (auto i = 0; i <= n; i++) { - // 打印行数 - cout << i << ":\t"; - - // 打印W列 - for (int w = 0; w <= W; w++) - { - cout << T[i][w] << "\t"; - } - - // 换行 - cout << endl; - } return T[n][W]; } @@ -51,15 +37,34 @@ int packRecursive(int n, int W, int *w, int *v) { return 0; } // 第i个物品不能装下,则递归装i-1个 - if (w[i] > W) { + if (w[n] > W) { return packRecursive(n - 1, W, w, v); } //第i个物品能装下,则比较包括第i个物品和不包括第i个物品,取其最大值 else { - return max(v[i] + packRecursive(n - 1, W - w[n], w , v), packRecursive(n - 1, W, w, v)); + return max(v[n] + packRecursive(n - 1, W - w[n], w, v), packRecursive(n - 1, W, w, v)); } } +// 打印背包问题的表格 +void printT(int n, int W) +{ + // 打印n行 + for (auto i = 0; i <= n; i++) + { + // 打印行数 + cout << i << ":\t"; + + // 打印W列 + for (int w = 0; w <= W; w++) + { + cout << T[i][w] << "\t"; + } + + // 换行 + cout << endl; + } +} int main() { int *w = NULL; // 存储每件物品重量的数组指针 @@ -94,8 +99,8 @@ int main() { // 分配空间 // 对w和v分配n+1大小 - w = new int[n+1]; - v = new int[n+1]; + w = new int[n + 1]; + v = new int[n + 1]; // 对T分配n+1行,并初始化为0 T = new int *[n + 1](); @@ -108,7 +113,7 @@ int main() { // 输入背包的重量和价值 for (auto i = 1; i <= n; i++) { - cout << "请输入第 " << i << " 个背包的重量和价值(用空格隔开)" << endl; + cout << "请输入第 " << i << " 个物品的重量和价值(用空格隔开)" << endl; cin >> w[i] >> v[i]; if (cin.fail() || w[i] < 0 || v[i] < 0) { @@ -134,6 +139,8 @@ int main() { { // 迭代法,能显示背包问题的表格 cout << "能装下物品的最大价值为 " << packIterative(n, W, w, v) << endl; + cout << "------------------------------------------------" << endl; + printT(n, W); break; } case 2: @@ -151,6 +158,13 @@ int main() { cout << "------------------------------------------------" << endl; + delete w; + delete v; + for (int i = 0; i <= n; ++i) { + delete[] T[i]; + } + delete[] T; + system("pause"); return 0; }