-
Notifications
You must be signed in to change notification settings - Fork 1
/
102.二叉树的层序遍历.cpp
55 lines (49 loc) · 1.34 KB
/
102.二叉树的层序遍历.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
#include "s.h"
/*
* @lc app=leetcode.cn id=102 lang=cpp
*
* [102] 二叉树的层序遍历
*/
// @lc code=start
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<vector<int>> levelOrder(TreeNode* root) {
if(root==nullptr) return {};
vector<vector<int> > ans;
queue<TreeNode *> q;
q.push(root);
int count1=1;
while(!q.empty()){
int count2=0;
vector<int> this_layer;
for(int i=0;i<count1;i++){
TreeNode *tmp = q.front();
q.pop();
this_layer.push_back(tmp->val);
if(tmp->left!=nullptr){
q.push(tmp->left);
count2++;
}
if(tmp->right!=nullptr){
q.push(tmp->right);
count2++;
}
}
ans.push_back(this_layer);
count1 = count2;
}
return ans;
}
};
// @lc code=end