**Incorrect evidence in dev set.**

[JosinaJoy]

          **Incorrect evidence in dev set.**

在 california_schools/frpm.csv 中，eligible free rate = Free Meal Count / Enrollment，同时 column 【Percent (%) Eligible Free (K-12)】确实是 【Free Meal Count (K-12)】 / 【Enrollment (K-12)】。

但是在 dev set中第一条测试数据就存在错误：

原始数据：

db_id: california_schools
question:
What is the highest eligible free rate for K-12 students in the schools in Alameda County?
evidence:
Eligible free rate for K-12 = FRPM Count (K-12) / Enrollment (K-12)
Gold SQL:
SELECT FRPM Count (K-12) / Enrollment (K-12)
FROM frpm
WHERE County Name = 'Alameda'
ORDER BY (CAST(FRPM Count (K-12) AS REAL) / Enrollment (K-12)) DESC LIMIT 1

两处错误：
(1) evidence 错误，正确的应该为 ： Eligible free rate for K-12 = Free Meal Count (K-12) / Enrollment (K-12)
(2) Gold SQL 写得复杂了，除法是多此一举。直接写成如下的即可，无需除法。因为 【Percent (%) Eligible Free (K-12)】就代表了 Eligible free rate for K-12

SELECT MAX(Percent (%) Eligible Free (K-12))
FROM frpm
WHERE County Name = 'Alameda';

或者

SELECT Free Meal Count (K-12) / Enrollment (K-12)
FROM frpm
WHERE County Name = 'Alameda'
ORDER BY (CAST(Free Meal Count (K-12) AS REAL) / Enrollment (K-12)) DESC LIMIT 1

类似的问题可能还有不少。

Originally posted by @wbbeyourself in #39 (comment)
Re-posting this issue as it is not clear what was the conclusion on this one. Why do we use 'Free Meal Count (K-12)AS REAL) /Enrollment (K-12)' when the calculated column - Percent (%) Eligible Free (K-12) exists in the DB?